A particle moves with an initial velocity v_(0) and retardation alphav, where alpha is a constant and v is the velocity at any time t. If the particle is at the origin at t=0 , find (a) (i) velocity as a function of time t. (ii) After how much time the particle stops? (iii) After how much time velocity decreases by 50% ? (b) (i) Velocity as a function of displacement s. (ii) The maximum distance covered by the particle. (c ) Displacement as a function of time t.
A point moves such that its displacement as a function of time is given by x^3 = r^3 + 1 . Its acceleration as a function of time t will be
The position of a particle varies with function of time as y=(4sin t+3cos t)m . Then the maximum displacement of the particle from origin will be
The acceleration of a particle at time is given by A=-aomega^(2) sinomegat . Its displacement at time t is
The rate of change of displacement with respect to time is known as velocity.If displacement of a particle is s=3t^(2)+4t+5 then velocity as a function of time
A particle moves in the x-y plane according to the law x=t^(2) , y = 2t. Find: (a) velocity and acceleration of the particle as a function of time, (b) the speed and rate of change of speed of the particle as a function of time, (c) the distance travelled by the particle as a function of time. (d) the radius of curvature of the particle as a function of time.
The displacement (x) of a particle as a function of time (t) is given by x=asin(bt+c) Where a,b and c are constant of motion. Choose the correct statemetns from the following.
If the velocity of a particle "v" as a function of time "t" is given by the equation,v=a(1-e^(-bt) ,where a and b are constants,then the dimension of the quantity a^2*b^3 will be
[" Velocity of a particle moving along "x" -axis "],[" as a function of time is given as "v=(4-],[t^(2))m/s," where "t" is time in second.The "],[" displacement of particle during "t=0s" to "t],[=1s" is "]
