When 1.80g glucose dissolved in 90g of H_(2)O ,the mole fraction of glucose is
9g of glucose and 3g of urea are dissolved in 1L of solution at 27^(@)C .The osmotic pressure of the solution will be
Calculating osmotic pressure: The fomula for low molecular mass starch is (C_(6)H_(10)O_(5))_(n) , where n averages 2.00xx10^(2) . When 0.798g of starch is dissolved in 100.0 mL of water solution, what is the osmotic pressure at 25^(@)C ? Strategy: Work out the molecular mass of (C_(6)H_(10)O_(5))_(200) , and use it to obtain the molarity of the starch solution. Substitute into the formula for the osmotic pressure, pi=CRT .
2g mixture of glucose and sucrose is dissolved in 1 litre water at 298K to develop osmotic pressure of 0.207 atm. Calculate percentage composition of glucose and sucrose by mole as well as by mass.
18 g glucose and 6 g urea are dissolved in 1 L aqueous solution at 27^(@)C . The osmotic pressure of the solution will be a. 8.826 atm , b. 4.926 atm ,c. 2.92 atm , d. 4.42 atm
Osomotic pressure at 300 K when 1g glucose (P_(1)),1g urea (P_(2)) and 1g sucrose (P_(3)) are dissolved in 500 ml of water are follows the order.
A solution of sucrose (mol. wt. 342 ) is prepared by dissolving 69.3 g of it per litre of the solution. What is the osmotic pressure at 300 K ?
10.0 g of glucose (pi_(1)) , 10.0 g of (urea (pi_(2)) , and 10.0 g of sucrose (pi_(3)) are dissolved in 250.0 mL of water at 273 K (pi= "osmotic pressure of a solution") . The relationship between the osmotic pressure pressure of the solutions is
1.46 g of a biopolymer dissolved in a 100 mL water at 300 K exerted an osmotic pressure of 2.42 xx 10^(-3) bar. The molar mass of the biopolymer is ________ xx 10^(4)g mol^(-1) . (Round off to the Nearest Integer)
