Four particles `A,B,C` and `D` with masses `m_(A)=m,m_(B)=2m, m_(C)=3m` and `m_(D)=4m` are at the comers of a square. They have accelerations of equal magnitude with directions as shown. The acceleration of the centre of mass of the particles is :
Four particles A, B, C and D with masses m_A = m, m_B = 2m, m_C = 3m and m_D = 4m are at the corners of a square. They have accelerations of equal magnitude with directions as shown. The acceleration of the centre of mass of the particles is:
Four particles A, B, C and D of masses m, 2m, 3m and 4m respectively are placed at corners of a square of side x as shown in Fig. Locate the centre of mass.
In the figure shown, the acceleration of block of mass m_(2) is 2m//s^(2) . The acceleration of m_(1) :
Four paticle of masses m_1 = 2 m, m_2 = 4 m, m_3 = m and m_4 are placed at four corners of a square. What should be the value of m_4 so that the centres of mass of all the four particle are exactly at the centre of the square ?
Four particle of masses m_(1)=2kg,m_2=4kg,m_(3)=1kg and m_(4) are placed at four corners of a square as shown in figure. Can mass of m_(4) be adjusted I such a way that the centre of mass of system will be at the centre of the square C.
If two particles of masses m_(1) and m_(2) are projected vertically upwards with speed v_(1) and v_(2) , then the acceleration of the centre of mass of the system is
Four particles of masses m, m, 2m and 2m are placed at the corners of a square of side a, as shown in fig. Locate the centre of mass.
Find the acceleration of the prism of mass M and that of the bar of mass m shown in figure.
Two particles of mass M and 2M are at a distance D apart. Under their mutual force of attraction they start moving towards each other. The acceleration of their centre of mass when they are D/2 apart is :
If four different masses m_1, m_2,m_3 and m_4 are placed at the four corners of a square of side a , the resultant gravitational force on a mass m kept at the centre is
