In an interference experiment the ratio of amplitudes of coherent waves is `(a_(1))/(a_(2))=(1)/(3)`. The ratio of maximum and minimum intensities of fringes will be:
In an interference experiment the ratio of amplitudes of coherent waves is a_1/a_2=1/3 The ratio of maximum and minimum intensities of fringes is …………..
The ratio of amplitudes of two coherent waves in Young's double-slit experiemnt is ( A_(1))/(A_(2)) =(1)/( 3) . What is the ratio of maximum and minimum intensities of fringes ?
If the ratio of the amplitudes of two waves is 4 : 3 , then the ratio of the maximu and minimum intensities is
If the ratio of the amplitudes of two interfering wave is 4:3, then the ratio of the maximumum and minimum intensities in the interference pattern is
Interference fringes are obtained due to the interference of wave from two coherent sources of light with amplitudes a_(1) and a_(2)(a_(1)=2a_(2)) . The ratio of the maximum and minimum intensities of light in the interference pattern is
The amplitude ratio of two superposing waves 3:1. what is the ratio of the maximum and minimum intensities?
If the ratio of amplitudes of two waves at any point in the medium is 1:3, then the ratio of maximum and minimum intensities due to their superposition will be -
If the ratio of amplitude of two waves is 4:3 , then the ratio of maximum and minimum intensity is
