In the figure shown, what is the current (in Ampere) drawn from the battery ? You are given: `R_(1) =15 Omega,R_(2)=10 Omega,R_(3)=20Omega,R_(4)=5Omega`, `R_(5)=25Omega,R_(6)=30Omega,E=15V`
In the figure shown, what is the current (in Ampere) drawn from the battery? You are given: R_1=15Omega R_2=10Omega R_3 =5Omega R_4=5Omega R_5=25Omega R_6=30Omega,E=150V
In the figure shown, what is the current (in Ampere) drawn from the battery? You are given: R _ 1 = 15 Omega, R _ 2 = 10 Omega, R _ 3 = 20 Omega, R _4 = 5 Omega, R _ 5 = 25 Omega , R _ 6 = 30 Omega, E = 15 V
The potential difference in volt across the resistance R_(3) in the circuit shown in figure, is (R_(1)=15Omega,R_(2)=15Omega, R_(3)=30Omega, R_(4)=35Omega)
A constant voltage V = 25 V is maintained between points A and B of the circuit (Fig). Find the magnitude and direaction of the current flowing through the segment CD if the resistances are equal to R_(1) = 1.0 Omega, R_(2) = 2.0 Omega, R_(3) = 3.0 Omega adn R_(4) = 4.0 Omega .
Determine the voltage drop across the resistor R_(1) in the circuit given below with E=60 V, R_(1)=18 Omega, R_(2)=10 Omega .
In Fig. 27-43, the current in resistance 6 is i_(6)= 2.80 A the resistances are R_(1)=R_(2)=R_(3)=2.00 Omega, R_(4)=16.0 Omega, R_(5)=8.00 Omega and R_(6)=4.00 Omega . Wat is the emf of the ideal battery?
Figure 27-11a shows a multiloop circuit containing one ideal battery and four resistances with the following values: R_(1)=20 Omega, R_(2)=20 Omega, epsi=12V , R_(3)=30 Omega, R_(4)=8.0 Omega (a) What is the current through the battery? (b) What is the current i_(2) through R_(2)? (c) What is the current i_3" through "R_3?
Determine the voltage drop across the resistor R_1 in the circuit given below with E = 65V, R_1 = 50 OmegaR_2 = 100 Omega, R_3 = 100 Omega, and R_4 300 Omega.
In the given cirucit, determine current through branch having indicated resistor R_(4) Given R_(1) = R_(2) = 4Omega, R_(3) = R_(4) R_(5) = 2Omega epsilon_(1) =5 V, epsilon _(2) =10V
