A string is clamped at both the ends and it is vibrating in its `4^(th)` harmonic. The equation of the stationary wave is `Y=0.3 sin(0.157x) cos(200pi t)`. The length of the string is : (All quantities are in SI units.)
A string is clamped at both the ends and it is vibrating in its 4^(th) harmonic. The equation of the stationary wave is Y=0.3 sin ( 0.157 x) cos (200 pi t) . The length of the string is: (All quantities are in SI units.)
A string fixed at both ends, oscillate in 4th harmonic. The displacement of particular wave is given as Y=2Asin(5piX)cos(100pit) . Then find the length of the string?
The equation of a stationary wave on a string clamped at both ends and vibrating in its third harmonic is given by y=0.5 sin (0.314"x") cos (600pit) where x and y are in cm and t is in sec. What is the length of the string?
The equation for the vibration of a string fixed at both ends vibrating in its third harmonic is given by y=2cm sin[(0.6cm^-1)x]cos[(500pis^-1)t] . The length of the string is
The equation of a stationary wave is y = 0.04 sin 200 pi t cos (pi x)/(0.3) with all quantities in SI units. What is the speed of the waves superposed ?
The equation for the vibration of a string fixed at both ends vibrating in its second harmonic is given by y=2sin(0.3cm^(-1))xcos((500pis^(-1))t)cm . The length of the string is :
A string fixed at both the ends of length 2m. Vibrating in its 7th overtone. Equation of the standing wave is given by y=Asinkxcos(omegat+(pi)/(3)) . All the symbols have their usual meaning. Mass per unit length of the string is 0.5(gm)/(cm) . Given that A=1 cm and omega=100pi(rad)/(sec) Answer the following 2 questions based on information given (use mu^(2)=10) Q. Starting from t=0 , energy of vibration is completely kinetic at time t t , where t is:
A string fixed at both the ends of length 2m. Vibrating in its 7th overtone. Equation of the standing wave is given by y=Asinkxcos(omegat+(pi)/(3)) . All the symbols have their usual meaning. Mass per unit length of the string is 0.5(gm)/(cm) . Given that A=1 cm and omega=100pi(rad)/(sec) Answer the following 2 questions based on information given (use mu^(2)=10) Q. Starting from t=0 , energy of vibration is completely potential at time t , where t is
If a string fixed at both ends, vibrates in its fourth harmonic, the wavelength is 15 cm. What is the length of the string ?
