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Let {:[(1,2),(0,1):}][{:(1,2),(0,1):}].....

Let `{:[(1,2),(0,1):}][{:(1,2),(0,1):}]......[{:(1,n-1),(0,1):}]=[{:(1,78),(0,1):}]`
If `A=[{:(1,n),(0,1):}]` then `A^(-1)=`

A

`[(1, 0),(12,1)]`

B

`[(1,-13),(0,1)]`

C

`[(1,-12),(0,1)]`

D

`[(1,0),(13,1)]`

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The correct Answer is:
B
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