The position of a particle as a function of time t, is given by `x(t)=at+bt^(2)-ct^(3)` where a,b and c are constants. When the particle attains zero acceleration, then its velocity will be :

Options

A. `a+(b^(2))/(4c)`
B. `a+(b^(2))/(3c)`
C. `a+(b^(2))/c`
D. `a+(b^(2))/(2c)`

Answer

A