A fas undergoes pysical adsorption on a surface and follows the given Freunflich adsorption isotherm equation `(x)/(m) = kp^(0.5)` Adorpation of the gas increase with :
A gas undergoes physical adsorption on a surface and follows the givn Freundlich adsoprtion isotherm equation x/m= kp^(0.5) . Adsorption of the gas increases with:
For Freundlich adsorption isotherm, (x)/(m)=kp^1//n , the value of n is
Freundlich adsorption isotherm is given by the expression (x)/(m) = kP^(1//n) . Then the slope of the line in the following plot is
Adsorption of a gas on a surface follows Freundlich adsorption isotherm. Plot of "log " (x)/(m) versus log P gives a straight line with slope equal to 0.5, then : ( (x)/(m) is the mass of the gas adsorbed per gram of adsorbent)
