A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only gravitational field of the planet acts on the spaceshop. What will be the number of complete revolutions made by the spaceship in 24 hours around the planet? [Given mass of plane `=8xx10^(22)kg` Radius of planet `=2xx10^(6)m` Gravitational constant `G=6.67xx10^(-11)Nm^(2)//kg^(2)`]
A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only gravitational field of the planet acts on the spaceship, what will be the number of complete revolutiions made by the spaceship in 24 hours around the planet? [Given : Mass of Planet =8xx10^(22) kg, Radius of planet =2xx10^(6) m, Gravitational constant G=6.67xx10^(-11)Nm^(2)//kg^(2) ]
Give the order of the following : Gravitational constant ( 6.67xx10^(-11)N-m^(2)//kg^(2) )
Calculate the gravitational force due to the earth on mahendra who has mass of 75kg. [mass of earth =6xx10^24 kg " Radius of the earth " = 6.4xx10^6m , " Gravitational constant " (G) = 6.67xx10^(-11) Nm^2//kg^2 ]
Calculate the force of gravitation due to earth on a ball of 1 kg mass lying on the ground.(Mass of earth =6xx10^(24) kg Radius of earth =6.4xx10^(3) km and G=6.7xx10^(-11)Nm^(2)/Kg^(2)
A synchronous satellite goes around the earth one in every 24 h. What is the radius of orbit of the synchronous satellite in terms of the earth's radius ? (Given: Mass of the earth , M_(E)=5.98xx10^(24) kg, radius of the earth, R_(E)=6.37xx10^(6)m , universal constant of gravitational , G=6.67xx10^(-11)Nm^(2)kg^(-2) )
Calculate the force of attraction between two balls each of mass 10kg when their centres are 10 cm apart. The value of gravitational constant G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)
Determine the binding energy of satellite of mass 1000 kg revolving in a circular orbit around the Earth when it is close to the surface of Earth. Hence find kinetic energy and potential energy of the satellite. [Mass of Earth =6xx10^(24)kg , radius of Earth =6400km , gravitational constant G=6.67xx10^(-11)Nm^(2)//kg^(2) ]
Calculate the mass of sum if the mean radius of the earth's orbit is 1.5xx10^(8)km and G=6.67xx10^(-11)Nxxm^(2)//kg^(2)
