Two blocks a and B of mass `m_(A)=1kg` and `m_(B)=3kg` are kept on the table as shown in figure the coefficient of friction between A and B is 0.2 and between B and the surface of the table is also 0.2 the maximum force F that can be applied on B horizontally, so that the block A does not slide over the block B is [Take `g=10m//s^(2)`]
