Two projectiles are thrown same speed in such a way that their ranges are equal. If the time of flights for the two projectiles are `t_(1)` and `t_(2)` the value of `'t_(1)t_(2)'` in terms of range `'R'` and `'g'` is
A projectile has a time of flight T and horizontal range R . If the time of flight is 1.5T ,what will be its range now?
A projectile can have the same range R for two angles of projection. If t_(1) and t_(2) be the times of flight in the two cases:-
A projectile has a time of flight T and range R . If the time of flight is doubled, keeping the angle of projection same, what happens to the range ?
A projectile has same range for two angules of projection. If times of flight in two cases are t_(1) and t_(2) then the range of the projectilie is
The relation between the time of flight of projectile T_(f) and the time to reach the maximum height t_(m) is
A projectille can have the same range R for two angles of projection. If t_(1) and t_(2) be the time of flight in the two cases, then find the relation between t_(1), t_(2) and R .
An object projected with same speed at two different angles covers the same horizontal range R. If the two times of flight be t_(1) and t_(2) . The range is 1/alpha "gt"_(1) t_(2), the value of alpha is
There are two values of time for which a projectile is at the same height. The sum of these two times is equal to (T = time of flight of the projectile)
For a given velocity, a projectile has the same range R for two angles of projection. If t_(1) and t_(2) are the time of flight in the two cases, then t_(1) = t_(2) is equal to
