A point charge is moving in a circular path of radius `10cm` with angular frequency `40pi` ra//s. The magnetic field produced by it at the center is `3.8xx10^(-10)T`. Then the value of charge is:
If a charged particle having charge q is moving in a circular path of radius R with a uniform speed u, what would be the magnetic field at the centre?
An electron is revolving in a circular path of radius 2xx10^(-10) m with a speed of 3xx10^(6) m/s. The magnetic field at the centre of circular path will be-
A charge of 10^(-6)C is describing a circular path of radius 1cm making 5 revolution per second. The magnetic induction field at the centre of the circle is
The momentum of alpha -particles moving in a circular path of radius 10 cm in a perpendicular magnetic field of 0.05 tesla will be :
A circular coil of radius 10 cm having 100 turns carries a current of 3.2 A. The magnetic field at the center of the coil is
A particle carrying a charge equal to 100 times the charge on an electron is rotating per second in a circular path of radius 0.8 metre . The value of the magnetic field produced at the centre will be ( mu_(0)= permeability for vacuum)
An alpha particle moves along a circular path of radius 2Å with a uniform speed of 2xx10^6ms^-1 . Calculate the magnetic field set up at the center of circular path.
A thin ring of 10 cm radius carries a uniformly distributed charge. The ring rotates at a constant angular speed of 40pi "rad s"^(-1) about its axis, perpendicular to its plane. If the magnetic field at its centre is 3.8xx10^(-9)T , then the charge carried by the ring is close to (mu_(0)=4pi xx10^(-7)N//A^(2))
