A wave is propagating in positive `x-`direction. A time `t=0` its snapshot is taken as shown. If the wave equation is `y=A sin(omegat-Kx+phi)`, then `phi` is
The equation y=A sin^2 (kx-omega t) represents a wave with
A wave propagates in a string in the positive x-direction with velocity v. The shape of the string at t=t_0 is given by f(x,t_0)=A sin ((x^2)/(a^2)) . Then the wave equation at any instant t is given by
In a wave motion y = a sin (kx - omegat) , y can represent
The equation y=Asin^2(kx-omegat) represents a wave motion with
Two longitudinal waves propagating in the X and Y directions superimpose. The wave equations are as below Phi_(1)=A(omegat-kx) and Phi_(2)=Acos(omegat-ky) . Trajectory of the motion of a particle lying on the line y=x((2n+1)lamda)/(2) will be
A wave is travelling along x-axis . The disturbance at x=0 and t=0 is A/2 and is increasing , where A is amplitude of the wave. If Y= sin (kx-omegat+phi) , then the initial phase is alpha pi . Find alpha
Equation y=y_(0) sin (Kx+omega t) represents a wave :-
Under what condition, maximum particle velocity is four times the wave velocity corresponding to the equation, y=A sin(omegat-kx)
_2019_CBT7_E01_013_Q01.png)
