The value of numerical aperature of the objective lens of a microscope is 1.25 if light of wavelength 5000 Å is used the minimum separation between two points to be seen as distinct, will be
The value of numerical aperture of the objective lens of a microscope is 1.25 .If light of wavelength 5000A^(@) is used then minimum separation between two points,to be seen as distinct is ?
The numerical aperture of objective of a microscope is 1*12 . The limit of resolution, when light of wavalength 6000 Å is used to view an object is :
The numerical aperture of an objective of a microscope is 0.5 and the wavelenght of light used is 5000Å . Its limit of resoluton will be
A telescope of diameter 2m uses light of wavelength 5000 Å for viewing stars.The minimum angular separation between two stars whose is image just resolved by this telescope is
If aperture diameter of the lens of a telescope is 1.25 m and wavelength of light used is 5000 Å its resolving power is
The diameter of the pupil of human eye is 2.5 mm. Assuming the wavelength of light used is 5000Å . What must be the minimum distance between two point like objects to the seen clearly if they are a distance of 5 m from the eye?
