Dimension of resistance R in terms of mu_0 & epsilon_(0) are
Dimension of epsilon_(0) are
The dimesions of (mu_(0) epsilon_(0))^(-1//2) are
The dimensions of epsilon_(0)mu_(0) are
The dimensions of (mu_(0)epsilon_(0))^(-1//2) are
If L has the dimensions of length, V that of potential and epsilon_(0) is the permittivity of free space then quantity epsilon_(0) LV has the dimensions of
Write the expression for speed of light in terms of 'mu_0 ' and 'epsi_0 explain the terms used.
A new system of unit is evolved in which the values of mu_(0) and epsilon_(0) aer 2 and 8 respectively. Then the speed of light in this system will be