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Consider f(x)=xsqrt(kx-x^(2)) for xepsil...

Consider `f(x)=xsqrt(kx-x^(2))` for `xepsilon [0, 3]`. Let `m` be the smallest value of `k` for which the function is increasing in the given interval and `M` be the largest value of `f(x)~ for that value of `k`. Then ordered pair `(m,M)` is

A

`(4,3sqrt2)`

B

`(4,3sqrt3)`

C

`(3,3sqrt3)`

D

`(5,3sqrt6)`

Text Solution

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The correct Answer is:
C
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