Three particles `A(50g), B(100g)` and `C(150g)` are placed at vertices of an equilateral triangle as shown in figure. Then the coordinates of center of mass of system is :
Three particles of massses 50 g, 100 g and 150 g are placed at the vertices of an equilateral triangle of side 1m ( as shown in the figure ) . The ( x, y) coordinates of the centre of mass will be :
Three particles , each of mass m, are placed at the vertices of a right angled triangle as shown in figure. The position vector of the center of mass of the system is (O is the origin and hat(i), hat(j), hat(k) are unit vectors)
Three charges Q, (+q) and (+q) are placed at the vertices of an equilateral triangle of side l as shown in the figure. It the net electrostatic energy of the system is zero, then Q is equal to
Three particles of masses 1 kg, (3)/(2) kg, and 2 kg are located the vertices of an equilateral triangle of side a . The x, y coordinates of the centre of mass are.
Three point particles of masses 1.0 kg, 1.5 kg and 2.5 kg are placed at three corners of a right angle triangle as shown in figure. The centre of mass of the system is at a point :
Three charges are placed at the vertex of an equilateral triangle as shown in figure. The value of Q, for which the electrostatic potential energy of the system is zero, is
Find the coordinates of the vertices of an equilateral triangle of side 2 a as shown in Figure.
Three particles of masses 0.50 kg, 1.0 kg and are placed at the corners of a right angle triangle, as shown in fig. Locate the centre of mass of the system.
Three particles, each of mass m are situated at the vertices of an equilateral triangle ABC of side l (as shown in the figure). The moment of inertia of the system about a line AX perpendicular to AB and in the plane of ABC, will be:
Three rods of the same mass are placed as shown in the figure. Calculate the coordinates of the centre of mass of the system.
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