`1kg` of water is at `20^(@)C`. A resistor of `20Omega` is connected across `200V` battery and the heat dissipated is supplied to water then the time taken by the water to evaporate is : (Specific heat `=4200 j//kg ^(@)C`, Latent heat `=2260kj/Kg`)
One kg of water, at 20^(@)C , is heated in an electric kettle whose heating element has a mean (temperature averaged) resistance of 20 Omega . The rms voltage in the mains is 200V. Ignoring heat loss from the kettle, time taken for water to evaporate fully, is close to: [specific heat of water= 4200J/kg ""^(@)C ], Latent heat of water = 2260kJ/kgI
10 litres of hot water at 70^@C is mixed with an equal volume of cold water at 20^@ C . Find the resultant temperature of the water. (Specific heat of water = 4200 J//kg -K ).
A pitcher contains 200kg of water 0.5 gm of water comes out on the surface of the pitcher every second through the pores and gets evaporated taking energy form the remaining water. Calculate the approximate time (in min) in which temperature of the water decreases by 5^(@)C . Neglect backward heat transfer form the atmosphere to th water. (Write the answer to the nearest interger) Specific heat capacity of water = 4200 J//Kg^(@)C Latent heat of vaporization of water 2.27 xx10^(6)J//Kg
One kilogram of ice at 0^(@)C is mixed with one kilogram of water at 80^(@)C . The final temperature of the mixture is (Take : specific heat of water =4200 J kg^(-1) K^(-1) , latent heat of ice = 336 kJ//kg^(-1) )
How much heat energy is gained when 5 kg of water at 20^(@)C is brought to its boiling point (Specific heat of water = 4.2 kj kg c)
Heat required to increases the temperature of 1kg water by 20^(@)C
Certain amount of heat is given to 100 g of copper to increase its temperature by 21^@C . If same amount of heat is given to 50 g of water, then the rise in its temperature is (specific heat capacity of copper = 400 J kg^(-1) K^(-1) and that for water = 4200 J kg^(-1) K^(-1))
