Assertion : The switch S shown in the figure is closed at t = 0 . Initial current flowing through battery is (E)/(R + r) Reason : Initially capacitor was uncharged, so resistance offered by capacitor at t = 0 is zero
The switch shown n the figure is closed at t=0 . The charge on the capacitor as a function of time is given by
In the circuit shown in figure switch S is closed at time t=0 Current I from the battery at time t is given by
In the circuit shown in figure switch S is closed at time t=0 . The charge which passes through the battery in one time constant is
The figure below shows a battery of emf epsilon connected to an inductor L and resistance R in series. If the switch is closed at t=0, then the total charge that flows from the battery in time constant of the circuit is
In the circuit shown in figure-3.240 switch S is closed at time t=0. find the current through different wires and charge stored on the capacitor at any time t.
The plates of a capacitor of capacitance C are given the charges Q_1 and Q_2 as shwon in figure. Now the switch is closed at t =0. Find the charges on plates after time t.
An inductance L and and a resistance R are connected in series to a battery of voltage V and negligible internal resistance through a switch. The switch is closed at t = 0 . The charge that passes through the battery in one time constant is [ e is base of natural logarithms]
In the circuit shown in figure-3.244, the battery is an ideal one with emf V. The capacitor is initially uncharged. The switch S is closed at time t=0. (a) Find the charge Q on the capacitor at time l (b) Find the current in branch AB at time just after closing the switch.
In the circuit shown in Figure, the battery is an ideal one, with emf V. The capacitor is initially uncharged. The switch S is closed at time t = 0 . (a) Find the charge Q on the capacitor at time t. (b) Find the current in AB at time t. What is its liniting value as t rarr oo : .
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