A line is at a distance of 4 units from ...

A line is at a distance of `4` units from origin and having both intercepts positive. If the perpendicular from the origin to this line makes and angle of `60^(@)` with the line `x+y=0`. Then the equation of the line is

`x +sqrt(3)y = 8`

`(sqrt(3)+1) x +(sqrt(3)-1) y = 8sqrt(2)`

`sqrt(3)x +y = 8`

`(sqrt(3) -1) x +(sqrt(3) +1) y = 8sqrt(2)`

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