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Calculate the resistance of an aluminium...

Calculate the resistance of an aluminium wire of length 50 cmand cross sectional area `2.0mm^(2)`. The resistivity of aluminium is `(rho)=2.6xx10^(-8)(Omega)m.`

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Verified by Experts

The resistance is R=(rho)(l)/(A)`
`=((2.6xx10^(-8)(Omega)m)xx(0.50m))/(2xx10^(-6) m^(2))=0.0065(Omega).`
We aarived at Ohm's law by making several assumption about the existence and behaviour of the free electrons. These assumptions are mot valid for semiconductors, insulators, solutions, ets. Ohm's law cannat be applied in such cases.
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HC VERMA-ELECTRIC CURRENT IN CONDUCTORS-Exercises
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  6. A current of 1.0 A exists in a copper wore of cross-section 1.0mm^(2)....

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  7. A wire of length 1 m and radius 0.1mm gas a resistance of 100(Omega).F...

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  9. Consider a wire of length 4m and cross-sectional areal 1 mm^(2) carryi...

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  11. Shown a conductor of length l having a circular cross section. The rad...

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  12. A copper wire of radius 0.1mm and resistance 1k(Omega)is connected acr...

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  13. Calculate the electric field in a copper wire of cross-sectional area2...

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  14. A wire has a length of 2.0m and a resistance of 5.0(Omega).Find the el...

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  15. The resistances of an iron wire and a copper wire at 20^(@)Care 3.9(Om...

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  16. The current in a conductor and the potential difference across its end...

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  17. Shown an arrangement to measure the emf (epsilon)and internal resistan...

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  18. The potential dofference between the terminals of a battery of emf6.0V...

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  19. The potential difference between the terminals of a 6.0V battery is 7....

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  20. The internal resistance of an accumulator battery of emf 6V is 10(Omeg...

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  21. Find the value of i(1)//I(2)in figure if (a)R=0.1(Omega) (b)R=1(Omega)...

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