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Find the equvalent resistance of the met...

Find the equvalent resistance of the metwork shown in figure between the point A and B.

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The 10(Omega) resistor and the 30(Omega) resistor are connected in parallel. The equivalent resistance between A and C is
`R_(1)=((10(Omega))(30(Omega)))/(10(Omega)+30(Omega))=7.5(Omega)`.
`This is connected with 2.5(Omega)in series. The equivalent resistance between A and B is`7.5(Omega)=2.5(Omega)=10(Omega)=10(Omega).`
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HC VERMA-ELECTRIC CURRENT IN CONDUCTORS-Exercises
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  13. Calculate the electric field in a copper wire of cross-sectional area2...

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  14. A wire has a length of 2.0m and a resistance of 5.0(Omega).Find the el...

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  15. The resistances of an iron wire and a copper wire at 20^(@)Care 3.9(Om...

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  16. The current in a conductor and the potential difference across its end...

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  17. Shown an arrangement to measure the emf (epsilon)and internal resistan...

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  18. The potential dofference between the terminals of a battery of emf6.0V...

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  19. The potential difference between the terminals of a 6.0V battery is 7....

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  20. The internal resistance of an accumulator battery of emf 6V is 10(Omeg...

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