Find the reactance of a capacitor `(C = 200 muF)` when it is connected to (a) `a 10 Hz AC source`, (b) `a 50 Hz AC` source and ( c) `a 500 Hz AC` source.

Explanation

The reactance is `X_c = 1/(omegaC) = 1/(2pivC)`.
(a) `X_c = 1/((2pi) (10 Hz) (200 xx 10^(-6) F)`
`= 80 Omega`
Similarly, the reactance is `16 Omega` for `50 Hz` and `1.6 Omega` for `500 Hz`.