Evaluate
(i) `root3((343)^(-2)) ` (ii) `root3((32)^(-3))`

Explanation

(i) `root3((343)^(-2)) = [(343)^(-2)]^(1//3) = (343)^((-2) xx(1)/(3))`
`= (7^(3))^(-(1)/(3)) = 7^([3xx(-(2)/(5))]) = 7^(-2) =(1)/(7^(2)) = (1)/(49)`
(ii) ` root5((32)^(-3)) = [(32)^(-3)]^((1)/(5)) = (32)^((-3)xx(1)/(5)) = (2^(5))^(-(3)/(4))`
` 2^([5xx(-(3)/(5))]) = 2^(-3) = (1)/(2^(3)) =(1)/(8)`