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Find the value of `x` in each of the following: `(3/5)^x\ (5/3)^(2x)=(125)/(27)` (ii) `5^(x-2)\ x\ 3^(2x-3)=135`

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We have .
`5^(x-2) xx 3^(2x -3) = 135 rArr 5^(x-2) xx 3^(2x - 3) = 5xx 3^(3)`
`rArr x -2 = 1 and 2x - 3 = 3`
`rArr x = 3`
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