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The value of sqrt((3-2sqrt(2))) is...

The value of `sqrt((3-2sqrt(2)))` is

A

`sqrt(3) + sqrt(2)`

B

`1-sqrt(2)`

C

`sqrt(2) + 1`

D

`sqrt(2)-1`

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( \sqrt{3 - 2\sqrt{2}} \), we can simplify the expression step by step. ### Step-by-Step Solution: 1. **Rewrite the expression**: We start with the expression \( \sqrt{3 - 2\sqrt{2}} \). 2. **Identify a perfect square**: We can express \( 3 \) as \( 2 + 1 \): \[ 3 - 2\sqrt{2} = (2 + 1) - 2\sqrt{2} \] 3. **Recognize the form of a square**: Notice that \( 2\sqrt{2} \) can be rewritten as \( 2 \cdot 1 \cdot \sqrt{2} \). This suggests that we can express the entire expression as a square: \[ 3 - 2\sqrt{2} = (\sqrt{2} - 1)^2 \] Here, \( a = \sqrt{2} \) and \( b = 1 \). Thus, we can confirm: \[ a^2 + b^2 - 2ab = (\sqrt{2})^2 + (1)^2 - 2(\sqrt{2})(1) = 2 + 1 - 2\sqrt{2} = 3 - 2\sqrt{2} \] 4. **Take the square root**: Now we can take the square root of both sides: \[ \sqrt{3 - 2\sqrt{2}} = \sqrt{(\sqrt{2} - 1)^2} \] 5. **Simplify the square root**: The square root of a square gives us the absolute value: \[ \sqrt{3 - 2\sqrt{2}} = |\sqrt{2} - 1| \] Since \( \sqrt{2} \) is approximately \( 1.414 \), which is greater than \( 1 \), we have: \[ |\sqrt{2} - 1| = \sqrt{2} - 1 \] ### Final Answer: Thus, the value of \( \sqrt{3 - 2\sqrt{2}} \) is: \[ \sqrt{2} - 1 \]
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