A solid toy is in the form of a right circular cylinder with a hemispherical shape at one end and a cone at the other end. Their common diameter is 4.2 cm. and the height of the cylindrical and conical portions are 12 cm and 7 cm respectively. Find the volume of the solid toy. (Use `pi=22//7` )

Explanation

The shape of the is given below
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Radius of the hemispherical part, `r=((4.2)/(2))cm= 2.1 cm `
Radius of the cylindrical part , r=2.1 cm
Radius of the conical part , r= 2.1 cm
Height of the cylindrical part , h = 12 cm
Height of the conical part , H=7 cm
Volume of the toy
= volume of the hemispherical part + volume of the cylinderical part +volume of the conical part
`=2/3pir^3+pir^2h + 1/3 pir^2H=pir^2(2/3r+h+ 1/3H)`
`=[22/7xx2.1 xx 2.1xx(2/3xx 2.1 + 12 +7/3)]cm^3`
`=(13.86 xx 47.2/3)cm^2= 218.064 cm^2`
Hence , the volume of the given toy is `218.064 cm^3`