How many spherical bullets can be made out of a solid cube of lead whose edge measures 44 cm, each being 4 cm in diameter.

Answer

`2541`

Explanation

Edge of the cube, a= 44 cm.
Volume of the cube = volume of the cuboid
`rArr a^3 =(44 xx 44xx 44) cm^3`
Radius of each spherical bullet r= 2 cm
Volume of each spherical bullet `= 4/3 pi r^3`
`=(4/3 xx 22/7xx 2xx2xx2)cm^3 =((704)/21)cm^3`
`therefore ` required number of bullets
`=("volume of the cube ")/("volume of each spherical bullet ")`
`(44xx 44 xx 44)/(704 // 21 )= 44 xx 44 xx 44 xx (21)/(704) = 2541`