A solid iron rectangular block of dimensions 4.4m, 2.6m and 1m is cast into a hollow cylindrical pipe of internal radius 30cm and thickness 5cm. Find the length of the pipe.

Answer

length of the pipe is 112 m.

Explanation

`"Volume of iron "=(440xx260xx100)cm^(3)`.
`"Internal radius of the pipe" = 30 cm^(3)`
External radius of the pipe = (30 + 5) cm = 35 cm.
Let the length of the pipe be h cm.
Volume of iron in the pipe
`=("external volume")-("internal volume")`
`=[pi(35)^(2)h-pi(30)^(3)=(325pih)cm^(3)`.
`:." "325pih = 440xx260xx100`
`rArr" length = h cm "=((440xx260xx100xx7)/(325xx22))cm`
`=112200 cm = 112 m.`
Hence the lenght of the pipe is 112 m.