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A tent is in the shape of a right circular cylinder up to a height of 3 m and conical above it. The total height of the tent is 13.5 m and the radius of its base is 14 m. Find the cost of cloth required to make the tent at the rate of ₹ 80 per square metre.[Take `pi = 22/7]`

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To find the cost of cloth required to make the tent, we need to calculate the curved surface area of the tent, which consists of a cylindrical part and a conical part. Here’s a step-by-step solution: ### Step 1: Identify the dimensions of the tent - The height of the cylindrical part (h₁) = 3 m - The total height of the tent (H) = 13.5 m - The radius of the base (r) = 14 m ### Step 2: Calculate the height of the conical part The height of the conical part (h₂) can be calculated as: \[ h₂ = H - h₁ = 13.5 \, \text{m} - 3 \, \text{m} = 10.5 \, \text{m} \] ### Step 3: Calculate the slant height of the cone To find the slant height (l) of the cone, we use the Pythagorean theorem: \[ l = \sqrt{r^2 + h₂^2} \] Substituting the values: \[ l = \sqrt{(14 \, \text{m})^2 + (10.5 \, \text{m})^2} \] \[ l = \sqrt{196 + 110.25} \] \[ l = \sqrt{306.25} \] \[ l = 17.5 \, \text{m} \] ### Step 4: Calculate the curved surface area of the cylinder The curved surface area (CSA) of the cylindrical part is given by: \[ \text{CSA}_{\text{cylinder}} = 2 \pi r h₁ \] Substituting the values: \[ \text{CSA}_{\text{cylinder}} = 2 \times \frac{22}{7} \times 14 \, \text{m} \times 3 \, \text{m} \] \[ \text{CSA}_{\text{cylinder}} = 2 \times \frac{22}{7} \times 42 \] \[ \text{CSA}_{\text{cylinder}} = \frac{1848}{7} \, \text{m}^2 \] \[ \text{CSA}_{\text{cylinder}} = 264 \, \text{m}^2 \] ### Step 5: Calculate the curved surface area of the cone The curved surface area of the conical part is given by: \[ \text{CSA}_{\text{cone}} = \pi r l \] Substituting the values: \[ \text{CSA}_{\text{cone}} = \frac{22}{7} \times 14 \, \text{m} \times 17.5 \, \text{m} \] \[ \text{CSA}_{\text{cone}} = \frac{22}{7} \times 245 \] \[ \text{CSA}_{\text{cone}} = \frac{5390}{7} \, \text{m}^2 \] \[ \text{CSA}_{\text{cone}} = 770 \, \text{m}^2 \] ### Step 6: Calculate the total curved surface area of the tent The total curved surface area (CSA_total) of the tent is the sum of the curved surface areas of the cylinder and the cone: \[ \text{CSA}_{\text{total}} = \text{CSA}_{\text{cylinder}} + \text{CSA}_{\text{cone}} \] \[ \text{CSA}_{\text{total}} = 264 \, \text{m}^2 + 770 \, \text{m}^2 \] \[ \text{CSA}_{\text{total}} = 1034 \, \text{m}^2 \] ### Step 7: Calculate the cost of cloth required The cost of cloth required is given by: \[ \text{Cost} = \text{CSA}_{\text{total}} \times \text{rate} \] Substituting the values: \[ \text{Cost} = 1034 \, \text{m}^2 \times 80 \, \text{₹/m}^2 \] \[ \text{Cost} = 82720 \, \text{₹} \] ### Final Answer The cost of cloth required to make the tent is ₹ 82,720. ---
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RS AGGARWAL-VOLUME AND SURFACE AREAS OF SOLIDS-Exercise 17A
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  10. A vessel is in the form of a hemispherical bowl surmounted by a hollow...

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  11. A toy is in the form of a cylinder with hemispherical ends. If the who...

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  13. A solid is in the form of a right circular cone mounted on a hemispher...

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  14. From a solid cylinder whose height is 8 cm and radius 6cm , a conical ...

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  15. From a solid cylinder of height 14 cm and base diameter 7 cm, two equa...

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  16. A metallic cylinder has radius 3 cm and height 5 cm, To reduce its wei...

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  17. From a solid cylinder of height 14cm and base diameter 7cm,two equal c...

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  18. A spherical glass vessel has a cylindrical neck 7 cm long and 4 cm in ...

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