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A toy is in the shape of a cone mounted ...

A toy is in the shape of a cone mounted on a hemisphere of same base radius. If the volume of the toy is 231 `cm^3` and its diameter is 7 cm, find the height of the toy

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To find the height of the toy, which consists of a cone mounted on a hemisphere, we will follow these steps: ### Step 1: Determine the radius of the base The diameter of the toy is given as 7 cm. Therefore, the radius \( r \) can be calculated as: \[ r = \frac{\text{diameter}}{2} = \frac{7 \, \text{cm}}{2} = 3.5 \, \text{cm} \] **Hint:** Remember that the radius is half of the diameter. ### Step 2: Write the formula for the volume of the toy The total volume \( V \) of the toy is the sum of the volume of the cone \( V_1 \) and the volume of the hemisphere \( V_2 \): \[ V = V_1 + V_2 \] Where: - Volume of the cone \( V_1 = \frac{1}{3} \pi r^2 h \) - Volume of the hemisphere \( V_2 = \frac{2}{3} \pi r^3 \) ### Step 3: Substitute the known values into the volume equation We know the total volume \( V = 231 \, \text{cm}^3 \) and we can substitute the expressions for \( V_1 \) and \( V_2 \): \[ 231 = \frac{1}{3} \pi r^2 h + \frac{2}{3} \pi r^3 \] ### Step 4: Factor out common terms Factoring out \( \frac{1}{3} \pi \) from both terms gives: \[ 231 = \frac{1}{3} \pi \left( r^2 h + 2r^3 \right) \] ### Step 5: Solve for \( h \) Rearranging the equation to isolate \( h \): \[ h + 2r = \frac{231 \times 3}{\pi r^2} \] Thus, \[ h = \frac{231 \times 3}{\pi r^2} - 2r \] ### Step 6: Substitute the value of \( r \) and \( \pi \) Using \( r = 3.5 \, \text{cm} \) and \( \pi \approx \frac{22}{7} \): \[ h = \frac{231 \times 3}{\frac{22}{7} \times (3.5)^2} - 2(3.5) \] ### Step 7: Calculate \( r^2 \) Calculating \( r^2 \): \[ (3.5)^2 = 12.25 \] ### Step 8: Substitute \( r^2 \) into the equation Now substituting \( r^2 \) back: \[ h = \frac{231 \times 3 \times 7}{22 \times 12.25} - 7 \] ### Step 9: Calculate the first term Calculating \( \frac{231 \times 3 \times 7}{22 \times 12.25} \): \[ = \frac{231 \times 21}{22 \times 12.25} = \frac{4851}{270.5} \approx 17.93 \] ### Step 10: Final calculation for \( h \) Now substituting back to find \( h \): \[ h = 17.93 - 7 \approx 10.93 \, \text{cm} \] ### Step 11: Total height of the toy The total height of the toy is the height of the cone plus the radius of the hemisphere: \[ \text{Total height} = h + r = 10.93 + 3.5 = 14.43 \, \text{cm} \] ### Final Answer The height of the toy is approximately \( 14.43 \, \text{cm} \). ---
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RS AGGARWAL-VOLUME AND SURFACE AREAS OF SOLIDS-Exercise 17A
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