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Let y=e^(2x)dotT h e n((d^2y)/(dx^2))((d...

`Let y=e^(2x)dotT h e n((d^2y)/(dx^2))((d^2x)/(dy^2))i s`

A

1

B

`e^(-2x)`

C

`2 e^(-2x)`

D

` - 2e^(-2x)`

Text Solution

Verified by Experts

The correct Answer is:
C

Given , ` y = e^(2x ) rArr (dy)/(dx) = 2a ^(2x) rArr (d^(2) y)/(dx^(2)) = 4a^(2x)`
Again consider ` y= e^(2x) rArr log y = 2x `
`rArr x= (1)/(2) ""log y`
`(dx)/(dy) = (1)/(2y) rArr (d^(2) x)/(dy^(2)) = - (1)/(2y^(2)) = - (1)/(2) e^(-4x)`
` therefore ((d^(2) y)/(ax^(2))) ((d^(2)x)/(dy^(2))) = 4e^(2x) (-(1)/(2)e^(-4x))`
` = - 2 e^(-2x)`.
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-DIFFERENTIATION -EXERCISE 2 (MISCELLANEOUS PROBLEMS)
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  2. If y=sqrt(x(log)e x) , then find (dy)/(dx) at x=e .

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  3. Let y=e^(2x)dotT h e n((d^2y)/(dx^2))((d^2x)/(dy^2))i s

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  4. If f(x)=|x-2| and g(x)=f(f(x)), then g'(x)"for "x gt 20,is

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  5. If y=(a+b x^(3/2))/(x^(5/4))a n dy^(prime)=0a tx=5, then the value o...

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  6. The value of (d)/(dx) (|x-1| + |x -5|) at x = 3 is

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  7. If y=f(x)" and "ycosx+cosy=pi, then the value of f''(0) is

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  8. Derivatives of y = cos^(-1) sqrt((cos 3x)/(cos ^(3) x)) with respect ...

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  9. if sqrt(x^2+y^2)=ae^(tan^-1 (y/x)) , a > 0, (y(0) > 0) then y"(0) equa...

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  10. If y = In ((x)/(a + bx))^(x), "then " x^(3)(d^(y))/(dx^(2)) is equa...

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  11. If (d^(2)x)/(dy^(2)) ((dy)/(dx))^(3) + (d^(2) y)/(dx^(2)) = k , then...

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  12. If f(x) = |cos x - sin x| , " then " '((pi)/(6)) is equal to

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  13. If f' (x) = sin (log x) and y = f((2x+3)/(3- 2x)), " then " (dy)/(...

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  14. If u = x^(2) + y^(2) " and " x = s + 3t, y = 2s - t , " then " (d^(2...

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  15. If the function f(x) is defined by f(x) = a + bx and f^(r) = fff … ...

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  16. If f(x) = x^(3) + x^(2) * f' (1)+ xf''(2) + f''(2) + f'''(3) , AA x i...

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  17. If x = tan""(y)/(2) - log[((1 + tan""(y)/(2))^(2))/(tan""(y)/(2))], "t...

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  18. If y=sec^-1([sqrtx+1]/[sqrtx-1])+sin^-1([sqrtx-1]/[sqrtx+1]), then dy/...

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  19. If y=(a^cos^((-1)x))/(1+a^cos^((-1)x)) and z=a^cos^((-1)x) , then (dy)...

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  20. If y= log x . e ^((tan x + x ^(2))), " then" dy/(dx) is equal to

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