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If y is a function of x and log(x+y)-2xy...

If `y` is a function of `x and log(x+y)-2xy=0` then the value of `y (0)` is equal to

A

1

B

`-1`

C

2

D

0

Text Solution

Verified by Experts

The correct Answer is:
A

At ` x = 0 , log (0 + y ) = rArr y = 1 `
Given , ` log (x + y) = 2xy`
`rArr (1)/(x+y) (1 +(dy)/(dx)) = 2x (dy)/(dx) + 2y *1`
`rArr (dy)/(dx) = (2y(x+ y)-1)/(1 - 2 (x + y)x)`
` rArr ((dy)/(dx))_((0,1)) = (2-1)/(1) = 1 `
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-DIFFERENTIATION -EXERCISE 2 (MISCELLANEOUS PROBLEMS)
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  14. If x^(y) = e^(2(x-y)), " then" f'(x) is equal to

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  18. If y = sin x^(@) " and " u = cos x " then " (dy)/(dx) is equal to

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  19. If y=tan^(-1)1/(1+x+x^2)+tan^(-1)1/(x^2+3x+3)+tan^(-1)1/(x^2+5x+7)++ u...

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