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If f(x)=sin^(-1)(sinx)+cos^(-1)(sinx) an...

If `f(x)=sin^(-1)(sinx)+cos^(-1)(sinx) and phi(x)=f(f(f(x)))`, then `phi'(x)` is equal to

A

1

B

`sin x `

C

0

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C

`f(x) = pi //2 ` (a constant function)
`[because sin^(-1) x + cos^(-1) x = (pi)/(2)]`
` therefore phi (x) = f(f((pi)/(2))) = (pi)/(2) rArr phi' (x) = 0 `
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