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Given that cos20^(@)-sin20^(@)=p , then...

Given that `cos20^(@)-sin20^(@)=p` , then what is the value of sin `40^(@)` ?

A

`1-p^(2)`

B

`1+p^(2)`

C

`p^(2)`

D

`p^(2)-1`

Text Solution

Verified by Experts

The correct Answer is:
A

As given , `cos20^(@)-sin20^(@)=p`
Squaring both sides , we get
`(cos20^(@)-sin20^(@))^(2)=p^(2)`
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  • If cos20^@ - sin 20^@ = p , then cos 40^@ is equal to

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    `p^2sqrt(2-p^2)`
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    `p^2sqrt(2-p^2)`
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    `p+sqrt(2-p^2)`
    D
    `p-sqrt(2-p^2)`
  • If "cos" 20^@ -"sin"^20^@=p , then "cos" 40^@ is equal to

    A
    `p^2sqrt(2-p^2)`
    B
    `psqrt 2-p^2)`
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