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For what values of x does the equation 4...

For what values of x does the equation `4sinx+3sin2x-2sin4x=2sqrt(3)` hold?

A

`(pi)/(6)`

B

`(pi)/(4)`

C

`(pi)/(3)`

D

`(pi)/(2)`

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To solve the equation \( 4\sin x + 3\sin 2x - 2\sin 4x = 2\sqrt{3} \), we will follow these steps: ### Step 1: Substitute \( x = \frac{\pi}{6} \) We start by substituting \( x = \frac{\pi}{6} \) into the equation. \[ 4\sin\left(\frac{\pi}{6}\right) + 3\sin\left(2 \cdot \frac{\pi}{6}\right) - 2\sin\left(4 \cdot \frac{\pi}{6}\right) \] ### Step 2: Calculate \( \sin\left(\frac{\pi}{6}\right) \) We know that: \[ \sin\left(\frac{\pi}{6}\right) = \frac{1}{2} \] Substituting this value into the equation gives: \[ 4 \cdot \frac{1}{2} = 2 \] ### Step 3: Calculate \( \sin\left(\frac{\pi}{3}\right) \) Next, we calculate \( \sin\left(2 \cdot \frac{\pi}{6}\right) = \sin\left(\frac{\pi}{3}\right) \): \[ \sin\left(\frac{\pi}{3}\right) = \frac{\sqrt{3}}{2} \] Substituting this value gives: \[ 3 \cdot \frac{\sqrt{3}}{2} = \frac{3\sqrt{3}}{2} \] ### Step 4: Calculate \( \sin\left(\frac{2\pi}{3}\right) \) Next, we calculate \( \sin\left(4 \cdot \frac{\pi}{6}\right) = \sin\left(\frac{2\pi}{3}\right) \): \[ \sin\left(\frac{2\pi}{3}\right) = \frac{\sqrt{3}}{2} \] Substituting this value gives: \[ -2 \cdot \frac{\sqrt{3}}{2} = -\sqrt{3} \] ### Step 5: Combine all the parts Now, we combine all the parts we calculated: \[ 2 + \frac{3\sqrt{3}}{2} - \sqrt{3} \] ### Step 6: Simplify the expression To simplify: \[ 2 + \frac{3\sqrt{3}}{2} - \frac{2\sqrt{3}}{2} = 2 + \frac{3\sqrt{3} - 2\sqrt{3}}{2} = 2 + \frac{\sqrt{3}}{2} \] ### Step 7: Find a common denominator We can express \( 2 \) as \( \frac{4}{2} \): \[ \frac{4}{2} + \frac{\sqrt{3}}{2} = \frac{4 + \sqrt{3}}{2} \] ### Step 8: Check if it equals \( 2\sqrt{3} \) Now we check if this is equal to \( 2\sqrt{3} \): \[ \frac{4 + \sqrt{3}}{2} = 2\sqrt{3} \] Multiplying both sides by 2 gives: \[ 4 + \sqrt{3} = 4\sqrt{3} \] ### Step 9: Solve for \( \sqrt{3} \) Rearranging gives: \[ 4 = 4\sqrt{3} - \sqrt{3} = 3\sqrt{3} \] Dividing by \( \sqrt{3} \): \[ \frac{4}{\sqrt{3}} = 3 \] ### Step 10: Final conclusion Thus, the original equation holds true for \( x = \frac{\pi}{6} \).

To solve the equation \( 4\sin x + 3\sin 2x - 2\sin 4x = 2\sqrt{3} \), we will follow these steps: ### Step 1: Substitute \( x = \frac{\pi}{6} \) We start by substituting \( x = \frac{\pi}{6} \) into the equation. \[ 4\sin\left(\frac{\pi}{6}\right) + 3\sin\left(2 \cdot \frac{\pi}{6}\right) - 2\sin\left(4 \cdot \frac{\pi}{6}\right) ...
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NDA PREVIOUS YEARS-TRIGONOMETRY - RATIO & IDENTITY , TRIGONOMETRIC EQUATIONS-MCQ
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  2. What is the value of (cos10^(@)-sin10^(@))/(cos10^(@)+sin10^(@))?

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  12. If secA+tanA=p , then what is the values of sin A?

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  14. For which acute angle theta,"cosec"^(2)theta=3sqrt(3)cottheta-5?

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  15. If tan^2theta=2tan^2phi+1, then which one of the following is correct?

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