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If 4sin^2 theta=1 where 0 ltthetalt2pi,...

If `4sin^2 theta=1` where `0 ltthetalt2pi`,= how many values does `theta`take?

A

1

B

2

C

4

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
C
`4sin^(2)theta=1`
`rArrsin^(2)theta=(1)/(4)rArrsintheta=+-(1)/(2)rArrtheta=+-(pi)/(6)`
Hence `theta` take 4 values . (one value for each quadrant)
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