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The line y=sqrt(3) meets the graph y...

The line `y=sqrt(3)` meets the graph `y=tanx` , where `x in(0, (pi)/(2))` , in k point . What is k equal to ?

A

One

B

Two

C

Three

D

Infinity

Text Solution

Verified by Experts

The correct Answer is:
A
Line `y=sqrt(3)and` graph y = tan x
Now , we have `sqrt(3)=tanx)`
`rArrtanx=tan60^(@)`
`rArrx=60^(@)" " [becausex in(0,(pi)/(2))]`
Hence , one intersecting point is possible in the given domain ie ., k = 1
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