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sin^(2)5^@+sin^(2)10^@+sin^(2)15^@ +.......

`sin^(2)5^@+sin^(2)10^@+sin^(2)15^@ +.......+sin^(2)85^@ + sin^(2)90^@=`

A

7

B

8

C

9

D

`(19)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`sin^(2)5^(@)+sin^(2)10^(@)+sin^(2)15^(@)+.........+.........+sin^(2)75^(@)+sin^(2)80^(@)+sin^(2)85^(@)+sin^(2)90^(@)`
`rArrsin^(2)5^(@)+sin^(2)10^(@)+sin^(2)15^(@)+.......sin^(2)(90-15^(@))+sin^(2)(90-10)+sin^(2)(90-5)+1`
`rArrsin^(2)5+sin^(2)10+sin^(2)15^(@)+.......+cos^(2)15^(@)+cos^(2)10^(@)+cos^(2)5^(@)+1`
`rArr(1+1+1+....8" times")_=+sin^(2)45^(@)+1`
`rArr8+(1)/(2)+1=(19)/(2)`
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NDA PREVIOUS YEARS-TRIGONOMETRY - RATIO & IDENTITY , TRIGONOMETRIC EQUATIONS-MCQ
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