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If sinalpha+sinbeta=0=cosalpha+cosbeta,...

If `sinalpha+sinbeta=0=cosalpha+cosbeta,"where"0 lt betaltalphalt2pi` , then which one of the following is correct ?

A

`alpha=pi-beta`

B

`alpha=pi+beta`

C

`alpha=2pi-beta`

D

`2alpha=pi+2beta`

Text Solution

Verified by Experts

The correct Answer is:
B
`sinalpha+sinbeta=0=cosalpha+cosbeta`
`sinalpha+sinbeta=0`
`rArrsinalpha=-sinbeta`
`rArrsinalpha=sin(pi+beta)`
`rArralpha=pi+beta`
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