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For x > 1, the minimum value of 2 log1...

For `x > 1`, the minimum value of `2 log_10(x)-log_x(0.01)` is

A

1

B

-1

C

2

D

`1//2`

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The correct Answer is:
D
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OBJECTIVE RD SHARMA-MAXIMA AND MINIMA -Chapter Test
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