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equation of tangent to y=int(x^2->x^3) (...

equation of tangent to `y=int_(x^2->x^3) (dt)/sqrt(1+t^2)` at `x=1` is:

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Equation of the tangent to y= int_(x^(2))^(x^(3)) (dt)/(sqrt(1+t^(2))) at x=1 is

The equation of tangent to the curve y=int_(x^(2))^(x^(3))(dt)/(sqrt(1+t^(2))) at x=1 is sqrt(3)x+1=y (b) sqrt(2)y+1=x sqrt(3)x+y=1(d)sqrt(2)y=x

The equation of the tangent to the curve y= int_(x^4)^(x^6) (dt)/( sqrt( 1+t^2) ) at x=1 is