The Hybridization of CH4 (methane) involves sp³ hybrid orbitals on the carbon atom. This hybridization allows carbon to form four sigma bonds with four hydrogen atoms, resulting in a tetrahedral molecular geometry. Let’s learn this concept in detail.
The hybridization of CH₄ (methane) is sp³. In methane, the carbon atom forms four sigma bonds with four hydrogen atoms. To accommodate these bonds, the carbon atom undergoes hybridization, leading to the formation of four equivalent sp³ hybrid orbitals. These orbitals then overlap with the 1s orbitals of the four hydrogen atoms, resulting in the tetrahedral molecular geometry of methane. Let’s understand hybridization of carbon in CH4 step by step -
1. Electron Configuration of Carbon :
Carbon's electron configuration is 1s22s22p2, indicating two electrons in the 1s orbital, two in the 2s orbital, and two in the 2p orbitals.
2. Valence Electrons :
Carbon has four valence electrons. Methane forms four sigma bonds with four hydrogen atoms, requiring four orbitals to accommodate these bonds.
3. Orbital hybridization of CH4 :
Carbon undergoes hybridization to form four equivalent orbitals suitable for sigma bonding.
4. Formation of Sigma Bonds :
5. Tetrahedral Molecular Geometry :
Methane (CH₄) is a simple hydrocarbon with essential properties, and a summary of Hybridization of CH₄ :
(Session 2025 - 26)