A cone is a three-dimensional geometrical figure with a circular base that narrows smoothly to an apex. Cones are one of the most fundamental geometric shapes that are used in mathematics, engineering, and everyday objects. Understanding the surface area and volume of cones is essential for students to grasp their real-life applications. This guide will explore the volume of cones and spheres and compare the volume of cones, cylinders, and spheres.
A cone is a 3-dimensional geometric shape with a circular base and a pointed edge on the top, called an apex. The line segment that joins the apex to the centre of the base is the height of the cone. Cones are commonly seen in everyday objects like ice cream cones, traffic cones, and funnels. Some of the sound properties of a cone are:
The volume of a cone is characterised by the amount of space it occupies. The standard volume of the cone formula is ⅓ 𝜋h, where
Here,
V represents the Volume of the cone,
r represents the Radius of its circular base, and
h represents the Height of the cone.
The volume of the cone, cylinder, and sphere can be compared using their respective formulas. Refer to the table below for a better understanding of the volume of cones and spheres as well as cylinders:
The surface area and volume of cones are two main concepts that every student needs to master. In addition to the volume of the cone formula, the surface area of cone is an important area that consists of the base area and the lateral surface area. Thus, the total surface area of the cone can be calculated with the formula:
A = πr (r + l)
Where A is the total surface area, r is the radius of the base, and l is the slant height.
Below are a few examples of the volume of cones that students must practice to grasp the concepts clearly.
Example 1. Find the volume (V) of a cone with a radius (r) of 4cm and a height (h) of 9cm.
We all know that V= ⅓ πr²h
So, using the formula, we can find
V= ⅓ x 3.1416 x 4² x 9;
V= ⅓ x 3.1416 x 16 x 9;
V ≈ 150.8 cm³.
Example 2: A company manufactures traffic cones with a base radius of 15 cm and a height of 45 cm. How much plastic material is needed per cone?
We all know that V= ⅓ πr²h
So, by putting all the values we find,
V = ⅓ π x 15² x 45;
V = ⅓ x 3.1416 x 225 x 45;
V ≈ 10610.1 cm³.
Thus, each cone will take approximately 10610 cm³ of plastic material.
Example 3: A conical tent has a volume of 6.6 m³ and a base radius of 1 meter. Find the Slant height of the tent in meters.
Solution: Given that the radius of the tent is 1m and the volume of the tent is 6.6m3. Therefore:
The volume of the tent (V) = ⅓ πr²h
Hence, the slant height of the tent is 6.38 m.
Example 4: The volume of a cone is 750 cm³. If the height is twice the radius, find the radius and height of the cone.
Solution: Given, volume of a cone is 750 cm3, and h = 2r
volume of a cone = 750 cm3
Practising problems related to surface area and volume of cone worksheets is important for mastering the topic. Below are some sample problems that you can work on to grasp the concepts better:
Understanding the volume of the cone formula is essential for students to grasp advanced mathematical concepts and real-world applications. By comparing it with the volume of a cone, cylinder, and sphere and practising relevant worksheets, students can master the concept. With practice, one can easily apply these principles in engineering, design, and daily life.
(Session 2025 - 26)