The `SI` unit of inductance, the henry can be written as

Options

A. (a) `weber//ampere`
B. (b) `volt - sec//amp`
C. ( c ) `joule//(ampere)^(2)`
D. (d) `ohm - second`

Answer

A, B, C, D

Explanation

(a,b,c ,d)
`L =(Phi)/(I), L = -e//((dI)/(dt)), L=(2U)/(I^(2), L =R xx t`
`L = ("Phi)/(I) = (weber)/(ampere)`
`L = (-e)/(dI//dt) = (vol t)/(ampere//sec) = (vol t-sec)/(ampere)`
`L=(2U)/(I^(2) = (joule)/((ampere)^(2))`
`L = R xx t =ohm - sec`