Let `[in_(0)]` denote the dimensional formula of the permittivity of vacuum. If `M = mass, L = length, T = time and A = elctric current, then :

Options

A. (a) `in_(0) = [M^(-1)L^(-3)T^(2)A]`
B. (b) `in_(0) = [M^(1)L^(3)T^(5)A^(2)]`
C. ( c ) `in_(0) = [M^(1)L^(2)T^(1)A^(2)]`
D. (d) `in_(0) = [M^(1)L^(-2)T^(1)A]`

Answer

B

Explanation

(b) As we know, `F = (1) /(4piepsilon_(0)) (q_(1)q(2))/(R^(2)) rArr epsilon_(0) = (q_(1)q_(2))/(4piFR^(2))`
Hence, `epsilon_(0) = [(AT)]^(2)/(MLT^(-2).L^(2)) = [M^(-2)L^(-3)T^(4)A^(2)]`