A ring shaped tube contain two ideal gases with equal masses and relative molar masses `M_1=32 and M_2=28.`
The gases are separated by one fixed partion and another movable stopper S which can move freely without friction inside the ring. The angle `alpha` as shown in the figure is ...... degrees.

Answer

A, B

Explanation

The movable stopper will adjust to a position with equal
Pressure on either sides. Applying ideal gas equation to the
two gases, we get
`PV_1=n_1RT=m/(M_1)RT,PV_2=n_2RT=m/(M_2)RT`
Hence, `(V_2)/(V_1)=(M_1)/(M_2)=32/28=8/7`
`alpha=(360^@)/(8+7)xx8=192^@`