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An ideal gas is initially at temperature...

An ideal gas is initially at temperature T and volume V. Its volume is increased by `DeltaV` due to an increase in temperature `DeltaT,` pressure remaining constant. The quantity `delta=(DeltaV)/(VDeltaT)` varies with temperature as

A

B

C

D

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Verified by Experts

The correct Answer is:
C

(c) We know that `v//t=constant`
`:. (V+DeltaV)/(T+DeltaT)=V/T or (DeltaV)/(VDeltaT)=1/T`
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