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Starting with the same initial conditions, an ideal gas expands from volume `V_1 to V_2` in three different ways. The work done by the gas is W_1 if the process is purely isothermal, `W_2`if purely isobaric and `W_3` if purely adiabatic. Then

A

`W_2gtW_1gtW_3`

B

`W_1gtW_2gtW_3`

C

`W_2gtW_3gtW_1`

D

`W_2gtW_1gtW_3`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) Work done is equal to area under the curve on PV
diagram.
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